Shell Script Program To Find Reverse Of A Number

clear

echo "Enter a number"

read n

sd=0

rev=0

while [ $n -gt 0 ]
do
    
    sd=$(( $n % 10 ))
    rev=$(( $rev * 10 + $sd ))
    n=$(( $n / 10 ))

done

echo "Reverse number of entered digit is $rev"